Termination w.r.t. Q of the following Term Rewriting System could not be shown:

Q restricted rewrite system:
The TRS R consists of the following rules:

g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))

Q is empty.


QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))

The set Q consists of the following terms:

g1(f2(x0, x1))


Q DP problem:
The TRS P consists of the following rules:

G1(f2(x, y)) -> G1(x)
G1(f2(x, y)) -> G1(g1(x))
G1(f2(x, y)) -> G1(y)
G1(f2(x, y)) -> G1(g1(y))

The TRS R consists of the following rules:

g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))

The set Q consists of the following terms:

g1(f2(x0, x1))

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
QDP

Q DP problem:
The TRS P consists of the following rules:

G1(f2(x, y)) -> G1(x)
G1(f2(x, y)) -> G1(g1(x))
G1(f2(x, y)) -> G1(y)
G1(f2(x, y)) -> G1(g1(y))

The TRS R consists of the following rules:

g1(f2(x, y)) -> f2(f2(g1(g1(x)), g1(g1(y))), f2(g1(g1(x)), g1(g1(y))))

The set Q consists of the following terms:

g1(f2(x0, x1))

We have to consider all minimal (P,Q,R)-chains.